#1653 Leetcode

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#1653 Leetcode Reel by @dailydoseofleetcode_yt - LeetCode 1461 Check If a String Contains All Binary Codes of Size K LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explan
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@dailydoseofleetcode_yt
LeetCode 1461 Check If a String Contains All Binary Codes of Size K LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation on YouTube (link in bio)
#1653 Leetcode Reel by @dailydoseofleetcode_yt - LeetCode 1689 Partitioning Into Minimum Number Of Deci-Binary Numbers LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full expl
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DA
@dailydoseofleetcode_yt
LeetCode 1689 Partitioning Into Minimum Number Of Deci-Binary Numbers LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation on YouTube (link in bio)
#1653 Leetcode Reel by @dailydoseofleetcode_yt - LeetCode 110 Balanced Binary Tree LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation on YouTube (link in bio)
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@dailydoseofleetcode_yt
LeetCode 110 Balanced Binary Tree LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation on YouTube (link in bio)
#1653 Leetcode Reel by @dailydoseofleetcode_yt - LeetCode 3637 Trionic Array I LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation on YouTube (link in bio)
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@dailydoseofleetcode_yt
LeetCode 3637 Trionic Array I LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation on YouTube (link in bio)
#1653 Leetcode Reel by @dailydoseofleetcode_yt - LeetCode 1784 Check if Binary String Has at Most One Segment of Ones LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full expla
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@dailydoseofleetcode_yt
LeetCode 1784 Check if Binary String Has at Most One Segment of Ones LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation on YouTube (link in bio)
#1653 Leetcode Reel by @dailydoseofleetcode_yt - LeetCode 3379. Transformed Array LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation on YouTube (link in bio)
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@dailydoseofleetcode_yt
LeetCode 3379. Transformed Array LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation on YouTube (link in bio)
#1653 Leetcode Reel by @dailydoseofleetcode_yt - LeetCode 762 Prime Number of Set Bits in Binary Representation LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation
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@dailydoseofleetcode_yt
LeetCode 762 Prime Number of Set Bits in Binary Representation LeetCode POTD explained clearly 💻 Problem → intuition → solution ⬆️ Full explanation on YouTube (link in bio)
#1653 Leetcode Reel by @skills2salary - This looks easy… But most people mess up the in-place logic. LeetCode 27 - Remove Element Given an array nums and a value val, remove all occurrences
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@skills2salary
This looks easy… But most people mess up the in-place logic. LeetCode 27 – Remove Element Given an array nums and a value val, remove all occurrences of val in-place and return the number of remaining elements. ⚠ Important: You cannot use extra space. The modification must happen inside the same array. 1️⃣ Use a slow pointer k to track valid elements 2️⃣ Traverse with fast pointer i 3️⃣ If nums[i] ≠ val → place it at nums[k] 4️⃣ Increment k This pattern appears in: ✔ Move Zeroes ✔ Remove Duplicates ✔ Partition problems ✔ Filtering in-place arrays ⏱ Time Complexity: O(n) 📦 Space Complexity: O(1) Master two pointers → unlock 20+ array problems. Follow for daily DSA breakdowns 🚀 #leetcode #twopointers #datastructures #algorithms #codinginterview
#1653 Leetcode Reel by @faangcracker_ - Leetcode permutation in string . . . #dsa #leetcode #lc438 #slidingwindow #hashmaps 🔍 Permutation in String - Pattern & Code Explanation 🚀 Probl
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@faangcracker_
Leetcode permutation in string . . . #dsa #leetcode #lc438 #slidingwindow #hashmaps 🔍 Permutation in String — Pattern & Code Explanation 🚀 Problem Overview Given two strings s1 and s2, return true if s2 contains any permutation of s1. In simple terms: check if any substring of s2 is an anagram of s1. --- 🧠 Pattern Used: Sliding Window + Frequency Map 💡 Core Idea We compare character frequencies instead of generating permutations. Steps: 1. Count character frequencies of s1. 2. Use a fixed-size sliding window over s2 with the same length as s1. 3. Update window counts as it moves. 4. If window frequency matches s1 frequency at any point, a permutation exists. --- ⏱ Complexity Time: O(n) where n is length of s2 Space: O(1) because only lowercase letters are stored Efficient and scalable. --- 🧩 Code Explanation Step 1: Count characters in s1 s1count stores frequency of each character in s1. Step 2: Sliding window over s2 window stores frequency of current window characters. Step 3: Expand window Each new character in s2 is added to the window count. Step 4: Maintain window size Once window size exceeds length of s1: • Remove leftmost character • Decrease its count • Delete if count becomes zero This keeps the window size fixed. Step 5: Compare maps If window equals s1count, we found a permutation. --- 🧠 Mental Model Instead of checking all permutations, ask: Does any window in s2 have the exact same character counts as s1? --- 🎯 Example s1 = "ab" s2 = "eidbaooo" Window movement: ei → no id → no db → no ba → match found → return true --- ⚠️ Common Mistakes Using sorting for each window causes slowdown Not removing zero-count characters breaks comparison Letting window grow beyond s1 length ruins logic --- 🔥 Why This Approach is Superior Brute force permutations are factorial time and impractical. Sliding window with frequency maps gives linear time. --- 🏁 Final Thoughts This pattern is critical for: • Anagram detection • Substring search problems • Pattern matching in strings • Efficient window-based algorithms Master this or struggle with string problems in interviews. If this clarified the logic, stop reading and impl

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