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THTwo cubics and neither one factors? Don't panic — subtract them 🧠
x³ + 2x² − 13x + 10
x³ + x² − 10x + 8
→ Subtract: x³ cancels, you get x² − 3x + 2
→ Factor: (x − 1)(x − 2)
→ Verify: plug x=1 and x=2 into both originals — all zeros ✅
H.C.F. = x² − 3x + 2
The trick? When both cubics have the same leading term, subtraction drops the degree and hands you the answer. Works every time.
Save this & follow for exam tricks your textbook skips 🔥
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