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'Insanity: Doing the same thing over and over again and expecting different results.' ~ Albert Einstein
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Let's find out if there is a capstone at the end of this recursive pyramid, shall we? . What do you think? πŸ€” . Journal, @mathematics.proofs, 18.08.2021, 15:23 BST . Music credits: https://www.bensoun
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I'm currently working on some new content for this page. . In the meantime here is a graph I made back on the 6th May 2021. . It's a recursive star pentagram and it was made on Desmos using the golden
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A point P on the line segment between two vectors A and B can be written as a weighted combination of A and B. If P divides the segment so that AP : PB = Ξ» : 1 βˆ’ Ξ» where 0 ≀ Ξ» ≀ 1 then we can mov
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The area of a parallelogram formed by two vectors is: Area = base Γ— height If the base is |A| and the height is |B|sin(ΞΈ), then: Area = |A||B|sin(ΞΈ) Now use the dot product identity: A Β· B = |A||
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Important identities for vector geometry Start with the ordinary algebraic identity: (x βˆ’ a)Β² = xΒ² βˆ’ 2ax + aΒ² This can also be written as: (x βˆ’ a)Β² = xΒ² + aΒ² βˆ’ 2ax In 2D: (x βˆ’ a)Β² + (y βˆ’ b)Β² = x
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Bayes’ theorem comes directly from the definition of conditional probability. Start with: P(A|B) = P(A ∩ B) / P(B) This means: P(A|B)P(B) = P(A ∩ B) Also: P(B|A) = P(A ∩ B) / P(A) This means:
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Derivative of ln x Let ln x = y Then x = eΚΈ Differentiate: dx/dy = eΚΈ Invert: dy/dx = 1/eΚΈ Substitute eΚΈ = x: dy/dx = 1/x, for x > 0 --- Derivative of aΛ£ Let y = aΛ£, a > 0, a β‰  1 Take
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An alternative for the equation of a circle. Apply Thales's Theorem and the Dot Product and you get a beautiful equation. xΒ²+yΒ²+x1x2+y1y2=(x1+x2)x+(y1+y2)y Free Desmos demo: https://desmos.com/calc
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A torus in ℝ³ from two circles. Start with a ring in the x–y plane: (r cos u, r sin u), 0 ≀ u ≀ 2Ο€, r β‰₯ 0. Now let the radius r and height z move around a circle in the r–z plane: r = a + d cos v, z
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The realm of ideas. Dimensions: 0D β†’ 4D, visualised in 2D. From a point to a line. From a line to a plane. From a plane to a cube. And then… beyond. #visualmath #pythagram #tesseract #geometry #dim
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An easy way to find the area distribution of one of the 3:4:5 right triangle hieroglyphs. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . #geometry #mathart #mathematics #tri
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About @mathematics.proofs

Mathematics Proofs is a Instagram micro influencer. With 65.9K followers and 12 posts, mathematics.proofs's account shows a follower-to-following ratio of 8237.3:1. This profile demonstrates strong community engagement within its niche. View all content anonymously on Pictame - no login required.

mathematics.proofs's engagement rate sits at 2.18%. For accounts with 10K-100K followers, the average is around 2.5%, so there's some room to grow β€” though every community is unique.

Out of the last 12 posts, 42% are videos and 58% are photos. Content shows up about every 196 days. Captions lean detailed, averaging 536 characters.

2.18% engagement rate β€” room to grow compared to average for 10K-100K follower accounts.
Posts about every 196 days.
8237.3:1 follower-to-following ratio.

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@mathematics.proofs

Mathematics Proofs

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A-Level Mathematics & Physics / Geometry / Graphs / Ray Tracing / Engineering

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